A Trapezoidal Piece Of Land Has A Parallel Sides That Measures 50 M And 38 M. These Sides Are 24 M Apart. If The Land Will Be Divided Equally In To 3

A trapezoidal piece of land has a parallel sides that measures 50 m and 38 m. These sides are 24 m apart. If the land will be divided equally in to 3 lots. What will be the area of each lot?

Answer:

The area of each lot would be 352 square meters.

Computation:

Solving for the area of the trapezoidal piece of land.

A=\frac{a+b}{2}h=\frac{38\:m+50\:m}{2}(24\:m)=44\:m(24\:m)=1,056\:m^{2}

Dividing the area of the land by 3.

1,056\:m^{2}/3=352\:m^{2}


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