2-Root5\Xf72+3root5=Aroot5+B., Find A And B

2-root5÷2+3root5=aroot5+b.
Find a and b

Answer:

The answers to this problem is a = 2.5 and b = 2.

Step-by-step explanation:

This problem deals with radicals and MDAS. As a technique, we can treat radicals as variables and perform the indicated operations with similar terms.

The solution for this problem goes like this

a\sqrt{5}+b = 2-\sqrt{5} /2 +3\sqrt{5}\\a\sqrt{5}+b = 2-\frac{1}{2}\sqrt{5} + 3\sqrt{5}\\a\sqrt{5}+b = 2 + 2.5\sqrt{5}\\a\sqrt{5}+b = 2.5\sqrt{5} + 2

Thus, a = 2.5 and b = 2.

If you want to know more about radicals, you may visit the following links:  

brainly.ph/question/2023247  

brainly.ph/question/1934207  

brainly.ph/question/1633897  


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